By Hans Dobbertin, Vincent Rijmen, Visit Amazon's Aleksandra Sowa Page, search results, Learn about Author Central, Aleksandra Sowa,
This booklet constítutes the completely refereed postproceedings of the 4th overseas convention at the complicated Encryption ordinary, AES 2004, held in Bonn, Germany in may possibly 2004. the ten revised complete papers provided including an introductory survey and four invited papers by way of best researchers have been rigorously chosen in the course of rounds of reviewing and development. The papers are geared up in topical sections on cryptanalytic assaults and comparable subject matters, algebraic assaults and similar effects, implementations, and different themes. All in all, the papers represent a latest overview of the cutting-edge of information encryption utilizing the complicated Encryption typical AES, the de facto global regular for facts encryption.
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Extra resources for Advanced Encryption Standard - AES: 4th International Conference, AES 2004, Bonn, Germany, May 10-12, 2004, Revised Selected and Invited Papers
Denote ˆL = a ˆ1 , a ˆ2 , . . , a ˆT , a ˆT +1 / the best linear / diﬀerential characteristic by Ω 1 2 T T +1 ˆD = ∆ˆ Ω . The data complexity of linear / diﬀerenx , ∆ˆ x , . . T ] (ˆ a1 , a ˆD ) . T ] (Ω (5) (6) If the resulting data complexity is prohibitive, the cipher is practically secure . 4 Linear Hulls and Diﬀerentials The concept of linear hulls is due to Nyberg . The counterpart for diﬀerential cryptanalysis is the concept of diﬀerentials, due to Lai et al. . Deﬁnition 3.
This remark permits to share in two parts the key exhaustive search and to improve the attack on a seven rounds-version of the AES by a factor 280 . 3 Outline of the Attack An eﬃcient exhaustive search of the kini , kτ1 and kτ2 keys could be performed in the following way: First step : Cipher the 232 chosen plaintexts for all possible values of the quartet (x0 , x1 , x2 , x3 ). Second step : For kini from (0,0,0,0) to (255,255,255,255) do Partition the (256)4 chosen plaintexts into (256)3 Λc sets according the value of the triplet c Choose into those (256)3 Λc sets 216 values of c For each value of the (c , c ) pair do For kτ1 from (0, · · · , 0) to (255, · · · , 255) do Compute the values of (τ1c ⊕ τ1c )y=0···15 from the ciphertexts Put them in a table Tkini ,c ,c [kτ1 ] End For For kτ2 from (0, · · · , 0) to (255, · · · , 255) do Compute the values of (τ2c ⊕ τ2c )y=0···15 from the ciphertexts Look in the table Tkini ,c ,c [kτ1 ] if the same values appear If yes, verify the same computation for all the y values If equality for all y values, return (kini , kτ1 , kτ2 ) Else continue End If End For End For End For Since the above procedure tests whether the exist collisions inside a random set of 2562 of the 2564 possible sc [y] functions, the probability of the procedure to result in a collision, and thus to provide kini , kτ1 and kτ2 is high (say about 1/2).
2 could be extended by one round at the beginning using the same method than the one proposed by the authors of Rijndael in the initial paper [DR98] and ﬁrst applied to the algorithm Square. e. (c0 , c1 , c2 ) stay a triplet of constants and y is the active byte). So, if all the 232 possible plaintexts are encrypted for all the possible values of the (x0 , x1 , x2 , x3 ) quartet (the other 12 bytes being taken equal to a constant), the 232 plaintexts could be partitioned, according to the value of kini , into 224 subsets of 28 plaintexts according the values of y (which are known up to an unknown constant linked with the ﬁrst round key byte).
Advanced Encryption Standard - AES: 4th International Conference, AES 2004, Bonn, Germany, May 10-12, 2004, Revised Selected and Invited Papers by Hans Dobbertin, Vincent Rijmen, Visit Amazon's Aleksandra Sowa Page, search results, Learn about Author Central, Aleksandra Sowa,